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Q:

Python: Finding period in a list that sum to a given number

I’m working on finding which tuple from a list sums to a given number. For example:
myList = [(1,2,3), (1,2,3), (1,2,3), (2,1,3), (1,3,3), (1,2,3)]

The tuple (1,3,3) only occurs twice in the list, so it’s the only tuple that can sum to 3. It’s the same with each one of the tuples. So, it’s not (1,2,3) because 2 does not give the sum of 3. Also, (2,1,3) doesn’t give the sum of 3 either.
I hope the above makes sense.
Here’s the code I have so far:
for i in myList:
sum = sum + i[1]
if sum == 3:
print(i)

I realize that this is going to just print all the tuples that sum to 3. I’m looking for a loop that just prints out the tuple that sums to 3, and any other tuples found that sum to 3. Any help is greatly appreciated.

A:

I would suggest this solution:
from collections import defaultdict

myList = [(1,2,3), (1,2,3), (1,2,3), (2,1,3), (1,3,3), (1,2,3)]

mydict = defaultdict(list)
for i in myList:
mydict[i[0]].append(i)

for k, v in mydict.items():
print(k, *v)

Output:
(1, 2, 3) (1, 2, 3)
(2, 1, 3) (1, 3, 3)

A:

for i in myList:
try:
return [j for k, v in mylist for j in (k+v if sum(map(sum, v))==3 and k>=0 else v) if k==i[0]]
except IndexError:

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